Adobe AD0-E200 Prüfungsthemen:
| Abschnitt | Ziele |
|---|---|
| Thema 1: Lösungsentwicklung | - Berichtssammlung und Datenkonfiguration
|
| Thema 2: Analyse und Bedarfsermittlung | - Erfassung von Geschäftsanforderungen
|
| Thema 3: Nach der Implementierung | - Prüfung und Steuerung
|
Adobe Analytics Architect AD0-E200 Prüfungsfragen mit Lösungen
A marketing decides to track search refinement that were selected in the search results page. A list was implemented to capture filters in propel using as the delimiter. Suppose a visitor made 10 search result pate view consistent refinement of sort1/sort3'. What will be page view count recorded in the prop1 report?
- A. 10 page views to sort/sort2/sort3
- B. 10 page views to sort3
- C. 10 page views each to sirt1.sort2. sort3
- D. 10 page views to sort2
- E. 10 page views to sort1
Antwort: A 🗳️
You have been asked to write technical specifications to add tracking to the internal search functionality of site. Given the following requirements. What is the most efficient solution to be implemented?
Custom eVar5 will capture the internal search term
Custom prop5 will capture the internal search term
Event3 is a customer event that is set each time a search occurs.
NOTE: Values in branches [ ] are dynamic meaning that they will vary based on the search term types by the site visitor A)
B)
C)
D)
- A. Option C
- B. Option B
- C. Option D
- D. Option A
Antwort: D 🗳️
Which of the following represents character limits for Context Data variables eVars, and prop?
- A. eVar: 255bytes. 00 bytes. Context data variables no character limits
- B. eVar: 255bytes. 100 bytes. Context data variables: 2k bytes
- C. eVar: 255bytes. 255 bytes. Context data variables 100 bytes
- D. eVar: 255bytes. 255 bytes. Context data variables: 255 bytes
Antwort: D 🗳️
What are the basis tenant of GDRP? Select three.
- A. First right of refusal
- B. Consent
- C. Right to access
- D. Right to be forgotten
- E. Right to partial access
Antwort: A,C,D 🗳️
Which javaScrip concatenates eVar2:prop2 inot prop1?
- A. s.prop1='D=c2+''.''+ v2
- B. s.prop1=D=c2+''.''+ v2
- C. s.prop1='D=c2+''.''+ v2
- D. s.prop1='D=c2+''.''+ c2
Antwort: C 🗳️
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